Answer:
None of the above
Explanation:
Work is defined as the force that moves an object through a particular distance:
Workdone = force x displacement
At constant velocity, the force on a body is zero because such a body is not accelerating.
Force is a product of mass and acceleration. Acceleration occurs only when velocity changes with time. If no change in velocity, acceleration does not occur. Therefore, no force is being applied.
From all the situations given, the condition is set at constant velocity. At constant velocity, there is no acceleration. This implies that no work is done.
An instrument which measure relative humidity is a hygrometer
Answer:
d =~ 5.8μm
d =~ 0.13 μm
Explanation:
when the doping concentrations are 5 × 10^15 cm^-3
d = v^-1/3 ; where d represent the distance between the atoms , and v represent the volume
d =1/ ∛v
d = 1/ ∛5 × 10^15
d = 1/ 170997.5
d = 5.85 × 10 ^ -6
d =~ 5.8μm
when the doping concentrations are 5 × 10^20 cm^-3
d = v^-1/3 ; where d represent the distance between the atoms , and v represent the volume
d =1/ ∛v
d = 1/ ∛5 × 10^20
using the principle of surds and standard forms, we have
d = 1/ ∛0.5 × 10^21
d = 1/7937005.26
d = 1.26 × 10 ^ -7
d = 0.126 × 10 ^ -6
d =~ 0.13 μm
Answer:
Partial pressure of O₂ = 0.0198 atm
Partial pressure of He = 0.1584 atm
Explanation:
Given data:
Mass of oxygen = 80.0 g
Mass of helium = 80.0 g
Total pressure = 0.1800 atm
Partial pressure of each gas = ?
Solution:
First of all we will calculate the number of moles.
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 32 g/mol
Number of moles = 2.5 mol
Number of moles of helium:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 4 g/mol
Number of moles = 20 mol
Total number of moles = 20 mol + 2.5 mol = 22.5 mol
Mole fraction of O₂ = 2.5 mol/ 22.5 mol = 0.11
Mole fraction of He = 20 mol / 22.5 mol = 0.88
Partial pressure:
Partial pressure of O₂ = 0.11× 0.1800 atm = 0.0198 atm
Partial pressure of He = 0.88 × 0.1800 atm = 0.1584 atm
Answer:
320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.
Explanation:
The balanced reaction is:
SO₃ + H₂O → H₂SO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- SO₃: 1 mole
- H₂O: 1 mole
- H₂SO₄: 1 mole
Being the molar mass of each compound:
- SO₃: 80 g/mole
- H₂O: 18 g/mole
- H₂SO₄: 98 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- SO₃: 1 mole* 80 g/mole= 80 grams
- H₂O: 1 mole* 18 g/mole= 18 grams
- H₂SO₄: 1 mole* 98 g/mole= 98 grams
Then you can apply the following rule of three: if 1 mole of sulfuric acid is produced by the reaction of 80 grams of sulfur trioxide, 4 moles of sulfuric acid is produced from how much mass of sulfur trioxide?
mass of sulfur trioxide= 320 grams
<u><em>320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.</em></u>
