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Arte-miy333 [17]
3 years ago
13

What is the m∠L? 45° 54° 40° 52°

Chemistry
1 answer:
Nataly [62]3 years ago
4 0

Answer:

m<L = 45

Explanation:

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Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
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Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

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3 years ago
What subatomic particle is most involved in making chemical bonds?
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Hen the space shuttle blasts into orbit, a hot gas forms when hydrogen and oxygen join to make water. this helps the space shutt
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Freon, a very useful refrigerant, is produced in the following reaction:
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Answer:

The chemistry will need 2*10⁶ moles of antimony trifluoride.

Explanation:

The balanced reaction is:

3 CCl₄ (g) + 2 SbF₃ (s) → 3 CCl₂F₂(g) + 2 SbCl₃ (s)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

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  • SbF₃: 2 moles
  • CCl₂F₂: 3 moles
  • SbCl₃: 2 moles

You can apply the following rule of three: if by reaction stoichiometry 3 moles of freon are produced by 2 moles of antimony trifluoride, 3*10⁶ moles of Freon are produced from how many moles of antimony trifluoride?

moles of antimony trifluoride=\frac{3*10^{6}  moles of freon*2 moles of antimony trifluoride}{3 moles of freon}

moles of antimony trifluoride= 2*10⁶

<u><em>The chemistry will need 2*10⁶ moles of antimony trifluoride.</em></u>

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