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3 years ago

Work is being done in which of these situations? All motions are at a constant velocity (including velocity = zero).

Chemistry

2 answers:

tigry1 [53]3 years ago

5 0

Answer:

None of the above

Explanation:

Work is defined as the force that moves an object through a particular distance:

Workdone = force x displacement

At constant velocity, the force on a body is zero because such a body is not accelerating.

Force is a product of mass and acceleration. Acceleration occurs only when velocity changes with time. If no change in velocity, acceleration does not occur. Therefore, no force is being applied.

From all the situations given, the condition is set at constant velocity. At constant velocity, there is no acceleration. This implies that no work is done.

riadik2000 [5.3K]3 years ago

3 0

the answer is A.) Jessica pushes a 25 kilogram cart a distance of 10 meters. for plato users :)

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ch4aika [34]

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3 years ago

A sample of 87.6 g of carbon is reacted with 136 g of

Vadim26 [7]

Answer:

A. fluorine, 1.79 moles

Explanation:

Given parameters:

Mass of carbon = 87.7g

Mass of fluorine gas = 136g

Unknown:

The limiting reactant and the maximum amount of moles of carbon tetrafluoride that can be produced = ?

Solution:

Equation of the reaction:

C + 2F₂ → CF₄

let us find the number of the moles the given species;

Number of moles = $\frac{mass}{molar mass}$

C; molar mass = 12;

Number of moles = $\frac{87.7}{12}$ = 7.31moles

F; molar mass = 2(19) = 38g/mol

Number of moles = $\frac{136}{38}$ = 3.58moles

So;

From the give reaction:

1 mole of C requires 2 moles of F₂

7.31 moles of C will then require 2 x 7.31 moles of F₂ = 14.62moles

But we have 3.58 moles of the F₂;

Therefore, the reactant in short supply is F₂ and it is the limiting reactant;

So;

2 moles of F₂ will produce mole of CF₄

3.58 moles of F₂ will then produce $\frac{3.58}{2}$ = 1.79moles of CF₄

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2 years ago

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2 years ago

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