Answer:
three consecutive odd integers: 2n-1 2n+1 2n+3
that the sum of the smaller two is three
times larger increased by seven: 2n-1 + 2n+1 = 3(2n+3) +7
4n = 6n+ 9 +7
4n = 6n+ 16
4n -6n = 16
-2n = 16
n = 16/(-2)
n=-8
a) 2n -1 = 2(-8) -1 = -17
b) 2n+1 = 2(-8)+1 = -15
c) 2n+1 = 2(-8)+3 = -13
Ans. -17 ; -15 ; -13
Answer:
25/12
Step-by-step explanation:
So first change the mixed numbers into improper fractions. 5/4 ad 5/3. Then just multiply them. 25/12.
I think the answer is 1d.
Answer:
See below
Step-by-step explanation:
<u>Given function</u>
<u>We can find its factors:</u>
- x³ + 3x² - 7x - 21 =
- x²(x + 3) - 7(x + 3) =
- (x² - 7)(x + 3)
We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)
Also one of zeros of the function is -3