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3 years ago

Please help me with this

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

7 0

I think the answer is d because when you solve it you come out to an approximate answer

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X-1/2 = 0.42 how do you solve ____ Algebraic division problems like th 4 This???? Please help!! Hduyeuridudufudycififufhdhcievkx

KatRina [158]

Answer:

$X=0.92$

Step-by-step explanation:

$X-\frac{1}{2} = 0.42\\$

Converting fraction into decimal.

$X-0.5=0.42$

Adding both side by 0.5

$X-0.5+0.5= 0.42+0.5\\\\X= 0.92$

5 0

3 years ago

How many cups of sugar is needed for 5 gallons

Alex

There are 16 cups in a gallon.

5 • 16 = 80

You need 80 cups of sugar for 5 gallons.

4 0

4 years ago

The sum of two numbers is 12, their product is 96. Compute these two numbers. Explain.

Anni [7]

Answer:

The numbers are

$6+2\sqrt{15}i$ and $6-2\sqrt{15}i$

Step-by-step explanation:

Let

x and y -----> the numbers

we know that

$x+y=12$ -----> $y=12-x$ ------> equation A

$xy=96$ ----> equation B

substitute equation A in equation B and solve for x

$x(12-x)=96\\12x-x^{2}=96\\x^{2} -12x+96=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} -12x+96=0$

$a=1\\b=-12\\c=96$

substitute

$x=\frac{-(-12)(+/-)\sqrt{-12^{2}-4(1)(96)}} {2(1)}$

$x=\frac{12(+/-)\sqrt{-240}} {2}$

Remember that

$i^{2}=\sqrt{-1}$

$x=\frac{12(+/-)\sqrt{240}i} {2}$

$x=\frac{12(+/-)4\sqrt{15}i} {2}$

Simplify

$x=6(+/-)2\sqrt{15}i$

$x1=6+2\sqrt{15}i$

$x2=6-2\sqrt{15}i$

we have two solutions

Find the value of y for the first solution

For $x1=6+2\sqrt{15}i$

$y=12-x$

substitute

$y1=12-(6+2\sqrt{15}i)$

$y1=6-2\sqrt{15}i$

Find the value of y for the second solution

For $x2=6-2\sqrt{15}i$

$y2=12-x$

substitute

$y2=12-(6-2\sqrt{15}i)$

$y2=6+2\sqrt{15}i$

therefore

The numbers are

$6+2\sqrt{15}i$ and $6-2\sqrt{15}i$

8 0

4 years ago

Please help!!! :)))))

Fudgin [204]

Answer:

An inscribed angle is an angle formed by two chords in a circle which have a common endpoint. This common endpoint forms the vertex of the inscribed angle. ... A central angle is any angle whose vertex is located at the center of a circle.

Step-by-step explanation:

9. Inscribed

10. Central

11. Central

12. Inscribed

13. Central

14. Inscribed

Hope this helped! ; )

6 0

4 years ago

Read 2 more answers

The length of a rectangular lot is 6 feet less than 3 times its

Katen [24]

Answer:

Length = 22.98 feet

Width = 9.66 feet

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Area of rectangle = 222 feet²

Translating the word problem into an algebraic expression, we have;

L = 3W - 6 ...... equation 1

We know that the area of a rectangle is given by the formula;

A = L * W

Substituting

222 = L * W ....equation 2

Substituting eqn 1 into eqn 2, we have;

222 = (3W - 6) * W

222 = 3W² - 6W

Rearranging the equation, we have;

3W² - 6W - 222 = 0

Next, we would use the quadratic formula to solve for the roots.

Note: the standard form of a quadratic equation is ax² + bx + c = 0

a = 3, b = -6 and c = -222

Solving the quadratic equation using the quadratic formula;

The quadratic equation formula is;

$x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}$

Substituting into the equation, we have;

$x = \frac {-(-6) \; \pm \sqrt {6^{2} - 4*3*(-222)}}{2*3}$

$x = \frac {6 \pm \sqrt {36 - (-2664)}}{6}$

$x = \frac {6 \pm \sqrt {36 + 2664}}{6}$

$x = \frac {6 \pm \sqrt {2700}}{6}$

$x = \frac {6 \pm 51.96}{6}$

$x_{1} = \frac {6 + 51.96}{6}$

$x_{1} = \frac {57.96}{6}$

x1 = 9.66

We do not need the negative value of x, so we proceed.

Therefore, Width, W = x1 = 9.66 feet

For the length;

L = 3W - 6

L = 3(9.66) - 6

L = 28.98 - 6

L = 22.98 feet

4 0

3 years ago