x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0
input into quadratic formula which is x=

or

si ax^2+bx+c
so a=1
b=-4
c=5
input

=

=

=
![\frac{4+2 times \sqrt{-1} }{2}= \frac{6 times \sqrt{-1} }{2}=3 times \sqrt{-1} [\tex][\tex]\sqrt{-1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%2B2%20times%20%20%5Csqrt%7B-1%7D%20%20%7D%7B2%7D%3D%20%20%5Cfrac%7B6%20times%20%20%5Csqrt%7B-1%7D%20%20%7D%7B2%7D%3D3%20times%20%20%5Csqrt%7B-1%7D%20%5B%5Ctex%5D%5B%5Ctex%5D%5Csqrt%7B-1%7D%20%20)
representeds by 'i' so solution is 3i
then if other way around then wyou would do

=

and [\tex]\sqrt{-1} [/tex] is represented by i
the solution is x=3i or i (i=

)
but i is not real, it is imaginary so there are no real solution so the answer is C
Answer:
The area of the rectangle would be 20 square units.
Step-by-step explanation:
The distance between the points (-8, -2) and (-3,-2) is 5. This is the length of the rectangle. The distance between (-3,-6) and (-3,-2) is 4. This is the width of the rectangle. To find the area, multiply the length and the width to get the 20 square units as the area.
Answer:
a)2*(15-s) mi
b)30mi
c) 30 mi
Step-by-step explanation:
Answer:

Step-by-step explanation:
3x^2 - 6x - 5=0
quadratic formula:

a=3 b=-6 c=-5


so we have:

Answer:
x = 4
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for x
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
(x + 3)² + (4(x + 2))² = 25² ← expand parenthesis on left side
x² + 6x + 9 + 16(x+ 2)² = 625
x² + 6x + 9 + 16(x² + 4x + 4) = 625
x² + 6x + 9 + 16x² + 64x + 64 = 625 ← simplify left side
17x² + 70x + 73 = 625 ( subtract 625 from both sides )
17x² + 70x - 552 = 0 ← in standard form
with a = 17, b = 70, c = - 552
Using the quadratic formula to solve for x
x = ( - 70 ±
) / 34
= ( - 70 ±
) / 34
= - 70 ±
) / 34
= - 70 ± 206 ) / 34
x =
= - 8.1176....
or x =
= 4
However, x > 0 ⇒ x = 4
Hence
x + 3 = 4 + 3 = 7 and
4(4 + 2) = 24
The triangle is a 7- 24- 25 right triangle