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3 years ago

Find f(-3) if f(x)=x2

Mathematics

2 answers:

Alja [10]3 years ago

5 0

Answer:

f(-3)=9

Step-by-step explanation:

We want to find what f(x), or y is, when x is equal to -3.

f(x)=x^2

We want to find f(-3). Therefore, we can substitute -3 in for x.

f(-3)=(-3)^2

Evaluate the exponent. -3^2 is the same as -3*-3.

f(-3)=-3*-3

f(-3)=9

zalisa [80]3 years ago

5 0

Answer:

f(-3)=9

Step-by-step explanation:

We want to find what f(x), or y is, when x is equal to -3.

f(x)=x^2

We want to find f(-3). Therefore, we can substitute -3 in for x.

f(-3)=(-3)^2

Evaluate the exponent. -3^2 is the same as -3*-3.

f(-3)=-3*-3

f(-3)=9

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Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

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