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o-na [289]
3 years ago
15

I NEED HELPP ASAP!!!!!!

Chemistry
2 answers:
alexdok [17]3 years ago
8 0
1. transformation
2. transfer
3. transformation
4. transfer

not 100% but hope it helped kinda
BlackZzzverrR [31]3 years ago
4 0
Transfer
Transformation
Transfer
Transformation
At least that’s what i think
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2

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Naming Compounds Test Review Practice Name the following ionic compounds: NH4Cl _____________________________________ Fe(NO3)3 _
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Answer :

The name of NH_4Cl is ammonium chloride.

The name of Fe(NO_3)_3 is iron(III) nitrate.

The name of TiBr_3 is titanium(III) bromide.

The name of Cu_3P is copper(I) phosphide.

The name of SnSe_2 is tin(IV) selenide.

The name of GaAs is gallium arsenide.

The name of Pb(SO_4)_2 is lead(IV) sulfate.

The name of Be(HCO_3)_2 is beryllium hydrogen carbonate.

The name of Mn_2(SO_3)_3 is manganese(III) sulfite.

The name of Al(CN)_3 is aluminium cyanide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) NH_4Cl

It is an ionic compound because it is formed by the combination of one polyatomic cation (ammonium ion) and anion (chloride ion). The charge on ammonium ion is (+1) and the the charge on chloride ion is (-1).

Thus, the name of NH_4Cl is ammonium chloride.

(b) Fe(NO_3)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (nitrate ion) and cation (iron ion). The charge on iron ion is (+3) and the the charge on nitrate ion is (-1).

Thus, the name of Fe(NO_3)_3 is iron(III) nitrate.

(c) TiBr_3

It is an ionic compound because it is formed by the combination of titanium cation and bromide anion. The charge on titanium is (+3) and the the charge on bromide ion is (-1).

Thus, the name of TiBr_3 is titanium(III) bromide.

(d) Cu_3P

It is an ionic compound because it is formed by the combination of copper cation and phosphorous anion. The charge on copper is (+1) and the the charge on phosphorous ion is (-3).

Thus, the name of Cu_3P is copper(I) phosphide.

(e) SnSe_2

It is an ionic compound because it is formed by the combination of tin cation and selenium anion. The charge on tin is (+4) and the the charge on selenium ion is (-2).

Thus, the name of SnSe_2 is tin(IV) selenide.

(f) GaAs

It is an ionic compound because it is formed by the combination of gallium cation and arsenic anion. The charge on gallium is (+3) and the the charge on arsenic ion is (-3).

Thus, the name of GaAs is gallium arsenide.

(g) Pb(SO_4)_2

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfate ion) and cation (lead ion). The charge on lead ion is (+4) and the the charge on sulfate ion is (-2).

Thus, the name of Pb(SO_4)_2 is lead(IV) sulfate.

(h) Be(HCO_3)_2

It is an ionic compound because it is formed by the combination of one polyatomic anion (hydrogen carbonate ion) and cation (beryllium ion). The charge on beryllium ion is (+2) and the the charge on hydrogen carbonate ion is (-1).

Thus, the name of Be(HCO_3)_2 is beryllium hydrogen carbonate.

(i) Mn_2(SO_3)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfite ion) and cation (manganese ion). The charge on manganese ion is (+3) and the the charge on sulfite ion is (-2).

Thus, the name of Mn_2(SO_3)_3 is manganese(III) sulfite.

(j) Al(CN)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (cyanide ion) and cation (aluminium ion). The charge on aluminium ion is (+3) and the the charge on cyanide ion is (-1).

Thus, the name of Al(CN)_3 is aluminium cyanide.

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A student needs to make a solution of 308 mL of 0.02 M of Copper (II) Sulfate. All they have available is a solution of 0.250 M.
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this link not hacl belive me

https://www.flinnsci.com/api/library/Download/18ce587821c24fb3b0ad7d878bd6a3d9Explanation:

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