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3 years ago

How much potassium nitrate can be dissolved in 100 grams of water at 30°C?

Chemistry

1 answer:

masya89 [10]3 years ago

3 0

Answer: In this case, you can estimate that the solubility of potassium nitrate in water at

∘

is equal to about

solubility

≈

110 g / 100 mL water

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

This tells you that a saturated solution of potassium nitrate will hold about

110 g

of dissolved salt, i.e. of dissociated salt, per

100 mL

of water at

∘

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Which of the following statements is true about the following reaction?

MAVERICK [17]

The correct reaction equation is:

$3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)$

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.

a) 22.4 L of $CO_{2}$ gas is produced only when $\frac{22.4}{3}$ L of $C_{6}H_{8}O_{7}$ is reacted with 22.4 L of $NaHCO_{3}$ . So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of $CO_{2}$ and $H_{2}O$ are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. Therefore it is correct option.

c) $6.02\times 10^{23}$ molecules is equal 1 mole of $Na_{3}C_{6}H_{5}O_{7}$ if produced then 3 moles of $NaHCO_{3}$ is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of $H_{2}O$ (Molecular Weight of water is 18 g) is produced when 3 moles of $NaHCO_{3}$ is used but in this option only one mole of $NaHCO_{3}$ is given. So it is wrong.

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3 years ago

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Which of the following statements about states of matter are not true

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Answer:

There is no answer choices

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Multiply the percentage by the mass for both and add them to get 63.545 amu

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4 years ago

Be sure to answer all parts. Write an unbalanced equation to represent each of the following reactions: Do not include phase abb

Eva8 [605]

Answer: The unbalanced chemical equations are written below.

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