Answer:
5.99×10⁶ m/s
Explanation:
We look for the speed of the electron by applying,
F = Bqv.................. Equation 1
Where F = Force on the electron, B = magnetic field, q = charge of an electron, v = speed of the electron.
make v the subject of the equation
v = F/Bq.............. Equation 2
Given: F = 2.4×10⁻¹² N, B = 2.5 T.
Constant: q = 1.602×10⁻¹⁹ C
Substitute into equation 2
v = 2.4×10⁻¹² /(2.5× 1.602×10⁻¹⁹ )
v = 5.99×10⁶ m/s
