Answer:
<h3><em>
28.01m/s.</em></h3>
Explanation:
Given maximum height reached by the ball as H = 40 metres
Since the ball rises straight up when hit by a ball, then the angle of launch will be perpendicular to the ground and that is 90°.
To determine the upward speed of the ball in meters per second after it got struck by the bat, we will use the formula for calculating the maximum height according to projectile motion;
Maximum Height H = 
where;
u is the speed of the ball
is the angle of launch
g is the acceleration due to gravity = 9.81m/s²
Substituting the given parameters into the formula;
<em>Hence the upward speed of the ball in meters per second after it got struck by the bat is 28.01m/s.</em>
Answer:
2√109 about 20.88
Explanation:
The mean of this set of numbers is (75+83+96+100+121+125)/6 is 100. Next step is ((75-100)^2+(83-100)^2+(96-100)^2+(100-100)^2+(121-100)^2+(125-100)^2)/6 this result is called deviation. Square root the deviation(436) then you set the standard deviation.
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Explanation:
Answer:
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