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sattari [20]
4 years ago
5

how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?

Physics
2 answers:
egoroff_w [7]4 years ago
8 0
F = m*a, mass times acceleration.

F = 15*10 = 150 N
Gwar [14]4 years ago
6 0

Answer:

150 Newtons

Explanation:

You might be interested in
In simple harmonic motion, the acceleration is proportional to In simple harmonic motion, the acceleration is proportional to:__
erik [133]

Answer:

e. all of the above

Explanation:

In simple harmonic motion, the acceleration is given as;

a = -ω²x = -(2πf)²x

a_{max} = -\omega ^2A

where;

ω is the angular velocity

f is the frequency

x is the displacement

A is the amplitude

Thus, In simple harmonic motion, the acceleration is proportional to the amplitude, velocity, frequency, and displacement.

The correct option is E.

"all of the above"

5 0
3 years ago
I need a bit of help on this one, can anyone answer?
emmainna [20.7K]

Potential energy = m · g · h

-- When you held the ball at 2.0 meters above the floor, it had

(0.5 kg) · (9.8 m/s²) · (2.0 m) = 9.8 Joules of potential energy.

-- After it bounced and went back up as high as it could, it was only 1.8 meters above the floor.  Its potential energy was

(0.5 kg) · (9.8 m/s²) · (1.8 m) = 8.82 Joules

-- Between the drop and the top of the bounce, it lost

(9.8 - 8.82) = <em>0.98 Joule</em> .

-- The energy was lost when the ball hit the floor.  During the hit, 0.98 joule of kinetic energy turned to <em>thermal energy</em>, which slightly heated the ball and the floor.

5 0
3 years ago
13 points!
skelet666 [1.2K]
I think it may be C!
4 0
3 years ago
Read 2 more answers
As an example, a 4.00-kg aluminum ball has an apparent mass of 2.10 kg when submerged in a particular liquid: calculate the dens
azamat

Answer:

1.2825 * 10^3 kg/m³

Explanation:

Given that :

Mass of aluminum ball (m1) = 4kg

Apparent mass of ball (m2) = 2.10 kg

Density of aluminum (d1) = 2.7 * 10^3 kg/m³

Density of liquid (d2) =?

Using the relation :

d1 / d2 = m1 / (m2 - m1)

(2.7 * 10^3) / d2 = 4 / (4 - 2.10)

2700 / d2 = 4 / 1.9

4 * d2 = 2700 * 1.9

4 * d2 = 5130

d2 = 5130 / 4

d2 = 1282.5 kg/m³

Hence, density of liquid = 1.2825 * 10^3

6 0
3 years ago
During a tug-of-war, team A pulls on team B by applying a force of 1550 N to the rope between them. The rope remains parallel to
yawa3891 [41]

Answer:

3565 J

Explanation:

F = Force applied = 1550 N

s = Displacement caused by the applied force = 2.3 m

\theta = Angle at which the force is applied = 0°

When we multiply force, displacement and the angle at which the force is applied we get work

Work done is given by

W=Fscos\theta\\\Rightarrow W=1550\times 2.3\times cos 0\\\Rightarrow W=3565\ J

The work done by team A is 3565 J

6 0
4 years ago
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