When iron forms an ion with a plus three charge, what is the formula of a compound with iron (fe3+) and sulfur (s)?

When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox

kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.

The catalyst surface area is directly proportional to the reaction rate

So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.

3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.

4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0

4 years ago

A compound has a molecular weight of 146 g/mol. A 0.3250 g sample of the compound contains 0.1605 g of carbon, 0.0220 g of hydro

Sonbull [250]

Answer: The molecular formula is $C_6H_{10}S_2$

Explanation:

We are given:

Mass of $C$ = 0.1605 g

Mass of $H$ = 0.0220 g

mass of $S$ = 0.1425 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.1605g}{12g/mole}=0.0134moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0220g}{1g/mole}=0.0220moles$

Moles of S = $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{0.1425g}{32g/mole}=0.0044moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.0134}{0.0044}=3$

For H = $\frac{0.0220}{0.0044}=5$

For S = $\frac{0.0044}{0.0044}=1$

The ratio of C : H: S= 3: 5: 1

Hence the empirical formula is $C_3H_5S$

The empirical weight of $C_3H_5S$ = 3(12)+5(1)+1(32)= 73g.

The molecular weight = 146 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{146}{73}=2$

The molecular formula will be= $2\times C_3H_5S=C_6H_{10}S_2$

7 0

3 years ago

The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.

torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

$Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}$

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0

3 years ago

Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-penten

Lemur [1.5K]

Answer:

Attached below

Explanation:

(a) 3-Methylcyclobutene

(b) 1-Methylcyclopentene

(c) 2,3-Dimethyl-2-pentene

(d) (Z)-3-Hexene

(e) (E)-2-Pentene

(f) 3,3,3-Tribromopropene

(g) (Z,4R)-4-Methyl-2-hexene

(h) (E,4S )-4-Chloro-2-pentene

(i) (Z)-1-Cyclopropyl-1-pentene

(j) 5-Cyclobutyl-1-pentene

(k) (R)-4-Chloro-2-pentyne

(l) (E)-4-Methylhex-4-en-1-yne

The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.

8 0

3 years ago

What is the first step in nucleophilic addition under acidic conditions?

damaskus [11]

Answer:

A nucleophile view the full answer Question 3 (1 point) What is the first step in nucleophilic addition under acidic conditions? Protonation of the nucleophile Addition of the nucleophile Loss of water Protonation of the carbonyl

Explanation:

5 0

3 years ago

Read 2 more answers