The molecular mass of the immunoglobulin G, given the data from the question is 1.53×10⁵ g/mole
<h3>How to determine the molarity</h3>
We'll begin by calculating the molarity of the immunoglobulin G. This is illustrated below:
- Volume = 0.106 L
- Temperature (T) = 25 °C = 25 + 273 = 298 K
- Osmotic pressure (π) = 0.733 mbar = 0.733 × 0.000987 = 0.00072 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
- Van't Hoff factor (i) = 1
- Molarity (M)
π = iMRT
M = π / iRT
M = 0.00072 / (1 × 0.0821 × 298)
M = 0.000029 M
<h3>How to determine the mole of immunoglobulin G</h3>
- Molarity = 0.000029 M
- Volume = 0.106 L
- Mole =?
Mole = Molarity × volume
Mole = 0.000029 × 0.106
Mole = 3.074×10⁻⁶ mole
<h3>How to determine the molar mass of mmunoglobulin G</h3>
- Mole = 3.074×10⁻⁶ mole
- Mass = 0.470 g
- Molar mass =?
Molar mass = mass / mole
Molar mass = 0.47 / 3.074×10⁻⁶
Molar mass = 1.53×10⁵ g/mole
Learn more about Osmotic pressure:
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Potassium carbonate reacts with barium chloride to precipitate insoluble barium salts that is barium carbonate, when the solutions are mixed together you'll see white precipitate that is barium carbonate and potassium is dissolve in the solution to form potassium chloride.
Answer:
2.5x10^–3 mole.
Explanation:
Data obtained from the question include:
Volume of solution = 25mL
Molarity of HNO3 = 0.1M
Mole of HNO3 =..?
First, we'll begin by converting 25mL to L. This can be achieved by doing the following:
1000mL = 1L
Therefore, 25mL = 25/1000 = 0.025L
Now, we can obtain the number of mole of HNO3 present in the solution as follow:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.1 x 0.025
Mole = 2.5x10^–3 mole.
Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.