Answer:
0.057 M
Explanation:
Step 1: Given data
Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴
Concentration of mercury (II) ion: 0.085 M
Step 2: Write the reaction for the solution of HgBr₂
HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻
Step 3: Calculate the bromide concentration needed for a precipitate to occur
The Ksp is:
Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²
[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M
Answer:
For iron
Final temperature = 54,22°C
For copper
Final Temperature = 63.67 °C
Explanation
Hello,
You are using a torch to warm up a block of iron that has an initial temperature of 32°C.
The first you have to know is that the "heat capacity" could simply define as the heat required to go from an initial temperature to a final temperature.
So you need to use the heat capacity equation as follow in the paper.
The equation has to have all terms in the same units, so:
q = 12000 J
s = 0.450 J / g °C
m = 1200 g
Ti = 32 °C
Answer:
1.53 × 10²³ molecules As₂O₃
Explanation:
Step 1: Define
Diarsenic Trioxide - As₂O₃
Avagadro's number: 6.02 × 10²³ atoms, molecules, formula units, etc.
Step 2: Use Dimensional Analysis
= 1.52908 × 10²³ molecules As₂O₃
Step 3: Simplify
We have 3 sig figs.
1.52908 × 10²³ molecules As₂O₃ ≈ 1.53 × 10²³ molecules As₂O₃
Answer:
Mass = 208.26 g
Explanation:
Given data:
Volume of water = 40.0 mL
Volume of water + copper = 63.4 mL
Volume of copper = ?
Density of copper = 8.9 g/cm³
Mass of copper = ?
Solution:
Volume of copper:
Volume of copper = (Volume of water + copper ) - Volume of water
Volume of copper = 63.4 mL - 40.0 mL
Volume of copper = 23.4 mL
Mass of copper:
density = mass/volume
8.9 g/cm³ = mass/23.4 mL
cm³ = mL
Mass = 8.9 g/mL × 23.4 mL
Mass = 208.26 g
Answer:
<h2>9 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 3 × 3
We have the final answer as
<h3>9 kg.m/s</h3>
Hope this helps you
