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Morgarella [4.7K]
3 years ago
14

What is the momentum of a 3 kg bowling ball moving at 3 m/s

Chemistry
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

<h2>9 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 3 × 3

We have the final answer as

<h3>9 kg.m/s</h3>

Hope this helps you

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Answer:

B. Lower than 100 °C because hydrogen sulfide has dipole-dipole interactions instead of hydrogen bonding.

Explanation:

Boiling point is a physical property which is usually a product of breaking intermolecular bonds.

Both dipole-dipole attractions are intermolecular bonds and they have serious effect on boiling point of a substance.

Hydrogen bonds are very strong intermolecular bonds compared to dipole-dipole attractions. In hydrogen bonding hydrogen atom is directly joined to a highly electronegative atom.

Dipole-Dipole attraction exists between molcules that are polar. Such molecules line up such that the positive pole of one molecule attracts the negative pole of another.

Hydrogen bonds in water are much stronger than the dipole-dipole attraction of hydrogen sulfide.

5 0
3 years ago
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A change that produces one or more new substances is called _____.
Vesnalui [34]

Answer:

the answer is c

Explanation:

a chemical change mean it changes it for ever and a physical change mean it can be changed back and evaporation means it turns solid water in to gas hope this helps

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3 years ago
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Anybody wanna have a decent conversation... btw I'm 17​
aleksandrvk [35]

Answer:

YES

Explanation:

8 0
3 years ago
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What is the energy released in the fission reaction 1 0 n + 235 92 U → 131 53 I + 89 39 Y + 16 1 0 n 0 1 n + 92 235 U → 53 131 I
mihalych1998 [28]

<u>Answer:</u> The energy released in the given nuclear reaction is 94.99 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{53}^{131}\textrm{I}+_{39}^{89}\textrm{Y}+16_{0}^1\textrm{n}

We are given:

Mass of _{92}^{235}\textrm{U} = 235.043924 u

Mass of _{0}^{1}\textrm{n} = 1.008665 u

Mass of _{53}^{131}\textrm{I} = 130.9061246 u

Mass of _{39}^{89}\textrm{Y} = 88.9058483 u u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(m_U+m_{n})-(m_{I}+m_{Y}+16m_{n})\\\\\Delta m=(235.043924+1.008665)-(130.9061246+88.9058483+16(1.008665))=0.1019761u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.1019761u)\times c^2

E=(0.1019761u)\times (931.5MeV)  (Conversion factor:  1u=931.5MeV/c^2  )

E=94.99MeV

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

3 0
3 years ago
Calculate the internal energy (in Joules) of a system that loses 134.8 J that is compressed with a pressure of 5.73 atm from 8.5
Nataly_w [17]

The change in the internal energy of the system is -4511.8 J.

<h3>What is the change in the internal energy?</h3>

We know that according to the first law of thermodynamics, energy can neither be created nor destroyed  but can be transformed from one form to the other.

Now we know that;

ΔE = q + w

ΔE = Change in internal energy

q = heat absorbed or evolved

w = work done

Now we have;

q = - 134.8 J (The system losses heat)

w = PdV

w =  5.73 (1.00 -  8.540)

w = -43.2 Latm or -4377 J

Then we have;

ΔE = - 134.8 J + (-4377 J)

ΔE = -4511.8 J

Learn more about internal energy:brainly.com/question/11278589

#SPJ1

5 0
1 year ago
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