Answer:
1
Step-by-step explanation:
The quadratic function
y = -2(x + 2)² - 1
has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)
A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:
y = -2(x + 2)² - 1 + 1 = -2(x + 2)²
which has point (-2, 0) as vertex
