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bagirrra123 [75]
3 years ago
8

Can someone explain me how to do this STEP BY STEP ?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0
In order to find the turning point, you need to find the rate of change of the slope.

At the turning point, the slope will be 0.

So, you should take the derivative of T(x): 

T(x)' = 3(x+5)^2, you will see only when x = -5, T(x)' = 0

So when x < -5, T(x)' >0, and x>-5, T(x)' > 0 as well

Therefore, the turning point is unique: x= -5
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Please show work!!!!!!!
kolezko [41]

Answer:

B

Step-by-step explanation:

The cylindrical part

Area of the cylindrical part = Circumference of the circle * height

Area of the cylindrical part = pi * d * height

Area = 3.14 * 10 * 9

Area =                                                                                282.6

Lid

Area = pi * r^2

r = 5

Area = 3.14* 5^2 * 2

Area =                                                                         <u>         157</u>

Total                                                                                    439.6                                                                        

I know this doesn't look right according to the diagram, but it is the only way that you can solve the question. That is, you must assume there are two lids, not one as the diagram suggests.

4 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
the perimeter of a picture frame is 24 inches if the width of the picture frame 5 inches what is the length of the picture frame
Ket [755]
You would divide 24 by 5 so the length would end up being: 4.8 in 
                  Hope it helps!
7 0
3 years ago
Describe the transformation done to y = 1/x to get y = 1/4x -12?
BabaBlast [244]
The transformation is done to y=1/x to get y=1/4x-12. We defined a turning point in the equation which will indicate the point in the graph.

We changed the form from y=x to y=x+c. In this case, we use 1/2 for the and constant C value which is -12.

3 0
3 years ago
Help please! Thank you
Anna71 [15]
First thing to do is set up your equation:
45/x = 20/100
Cross multiply
4500 = 20x
And divide by 20

Answer: 225 people were surveyed 

6 0
3 years ago
Read 2 more answers
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