Answer:
32.008
Step-by-step explanation:
I think that it's B, y = -x - 7 because first you'd subtract y to get it on the other side then add x and then you'd need to make the y positive so you would divide x + 7 by -1 and that would make it y = -x - 7.
Answer:
$6,427.99
Step-by-step explanation:
-We first find the effective annual interest rate as follows:
#We the use this rate to find the compounded amount after 18 years:
Hence, the amount after 18 years is $6,427.99
For this case we are going to define the following variable:
x: time in minutes
We write the linear function that represents the problem:
t (x) = (14/4) x + 7
For x = 6 we have:
t (6) = (14/4) * (6) + 7
t (6) = 28 ° C
For x = 11 we have:
t (11) = (14/4) * (11) + 7
t (11) = 45.5 ° C
Answer:
t (6) = 28 ° C
t (11) = 45.5 ° C
My answer -
<span>1. Use symbols (not words) to express quotient
2. Use exponent symbol (^) to denote exponents
3. Just write out question number, question, and choices. No need for
extra information (such as points). Also, don't leave blank lines
between choices. This extraneous that we don't need just makes your
whole question very very long, and means a lot of scrolling on our part.
4. You should only post 2 or 3 questions at a time.
1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !
2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !
3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36
4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20
5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2
6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6
7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial
8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6
9) (x − 1) + (2x + 5) − (x + 3) = x + 1
10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4
Last question shows why it is so important to use proper symbols (such
as ^ to indicate exponents). Without such symbols, I could not tell if
the 0 was an actual number and part of multiplication, of if 0 was an
exponent of the expression preceding it.
P.S
Glad to help you have an AWESOME!!! day :)
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