All categories

3 years ago

find the measure of the vertex anlge of an isosceles triangle if the measure of one base angle is 36°

1 answer:

5 0

Because it is an isosceles triangle, the two base angles have to be the same, so
36°+36°=72°
angles in all triangles add up to 180°, so
180°-72°=108°
unknown=108°

You might be interested in

Simplify expression 2i(4.5-20i)3i

Margaret [11]

Answer:

-27+120i

Step-by-step explanation:

that is the answer

3 0

3 years ago

You randomly choose one of the tiles. Without replacing the first tile, you randomly choose a second tile. Find the probability

Lesechka [4]

Answer:

4/21

Step-by-step explanation:

I got the first probability and the second probabilty then multiplied them together.

3 0

3 years ago

the perimeter of rectangular garden is 64 centimeters .the length of garden is three times the width .find the lenght

kakasveta [241]

Answer:

length= 24cm

Step-by-step explanation:

interpreting the question

L=3w

perimeter=2(l+w)

64=2(3w+w)

64=2(4w)

64=8w, Divide both sides by 8

w= 8cm

since w= 8

L=3w

L=3×8

L=24cm

6 0

3 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

Helpppppppppppppppppp

pochemuha

Answer:

what do you need help with ???

4 0

3 years ago