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3 years ago

Find the difference between the polynomials:–3x+x3–2x2 and 4x3–2x2–4x

Mathematics

1 answer:

allsm [11]3 years ago

5 0

Answer:

x-3x^3

Step-by-step explanation:

^ means to the power of btw

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5 is a prime number of 2475 what are the other two numbers

ArbitrLikvidat [17]

$2475=3^2\cdot5^2\cdot11$

The two other prime factors are 3 and 11

6 0

3 years ago

Please help solve this with working out :)

Anastaziya [24]

I hope this can help u

3 0

2 years ago

A 2-column table has 4 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1. The second column is label

JulijaS [17]

The growth factor of the exponential function represented by the table is 5.

The correct option is c.

<h3>What is the growth factor of the exponential function?</h3>

The growth factor of the exponential function is the ratio of the two consecutive terms (y-values).

The growth factor of the exponential function is given by;

$\rm Growth\ factor=\dfrac{y(x_2)}{y(x_1)}\\\\$

As per given, we have a table;

x y

-2 0.004

-1 0.02

0 0.1

1 0.5

The value $\rm x_2$ is -2 and $\rm x_1$ is -1.

Therefore,

the growth factor of the exponential function represented by the table would be :

$\rm Growth\ factor=\dfrac{y(x_2)}{y(x_1)}\\\ \rm Growth\ factor=\dfrac{y(-1)}{y(-2)}\\\\\rm Growth\ factor=\dfrac{0.02}{0.004}\\\\ \rm Growth\ factor=5$

Hence, the growth factor of the exponential function represented by the table is 5.

To know more about the Growth factor click the link given below.

brainly.com/question/985668

6 0

2 years ago

Common factors of 35 and 60

OLga [1]

Factors of 35: 1; 5; 7; 35
Factors of 60: 1; 2; 3; 4; 5; 6; 10; 12; 15; 20; 30; 60

<span>Greatest Common Factor GCF(35; 60) = 5</span>

4 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago