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melamori03 [73]
2 years ago
11

Calculate the first and second

Mathematics
1 answer:
LenKa [72]2 years ago
3 0

Answer:

Hi,

Step-by-step explanation:

\begin{array}{|c|c|c|c|}x&3x^2+5&\Delta_1x&\Delta_2x\\--&--&--&--\\0&5&-&-\\1&8&3&-\\2&17&9&6\\3&32&15&6\\4&53&21&6\\--&--&--&--\\\end{array}

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I'm need help a question and I'm confuse.
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Answer:

Step-by-step explanation:

Since angle ABD is 133 degrees and the sum of the angles in a triangle is 180 degrees, it means that

m∠ DAB + 133 + 22 = 180

m∠ DAB = 180 - 155 = 25 degrees

Also, ∆ ADC is an isosceles triangle because two of its sides are equal. It also means that the base angles are equal. Thus,

m∠ A = m∠ B

Therefore,

m∠ A + m∠ B + angle D = 180

m∠ A + m∠ B = 180 - 22 × 2

m∠ A + m∠ B = 180 - 44 = 136

m∠ A = m∠ B = 136/2 = 68 degrees

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Therefore,

m∠ CAB = 68 - 25 = 43 degrees

Since ∆ ABC is isosceles, then

m∠ CAB = m∠ ACB

m∠ ACB = 43 degrees

m∠ ABC = 180 - (43 × 2) = 180 - 86

m∠ ABC = 94 degrees

m∠ BCD = 68 - m∠ ACB

m∠ BCD = 68 - 43 = 25 degrees

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Just multiply.

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Step-by-step explanation:

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