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QveST [7]
3 years ago
15

E) What is the measure of

Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

I am pretty sure it is 135 degrees, but I still do not know. They don't give you any angles, so I think you're supposed to use a protractor.

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A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

The 95 percent confidence interval estimate for the​ mean:(190.14, 295.06)

8 0
3 years ago
An inventor receives 4% of the cost of every product a company sells. If the company sells $5,000 worth of product, how much doe
andrew-mc [135]

Answer:

The investor receives $200

Step-by-step explanation:

In order to find this, simply multiply the percentage by the total amount.

$5,000 * 4%

$5,000 * .04

$200

4 0
3 years ago
show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
VLD [36.1K]

Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

8 0
3 years ago
Use the distance to find the distance between the points A (-3,7 and B (-2,5).
Eva8 [605]

Step-by-step explanation:

1 2 3 4 5

wa

6 0
3 years ago
Will crown brainiest for the correct answer<br> plz read and answer<br> try ur best and good luck
eduard

Answer:

53%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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