It is a rectangular pyramid
should i explain?
fell free to tell me if it doesn't make sense :)
Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
Here, we will use the formula from trigonometry which defines a radian
we know that an angle is a radian when the length of the radius of the circle is equal to the length of the arc formed
hence, if the radius is r and the arc is r, the angle (in radians) will be 1
if the radius is r and the arc is 2r, the angle in radians will be equal to:
length of arc / radius = 2r/r = 2 radians
I believe this will explain what is actually happening in these type of questions
So, the equation:
Θ(in radians) = s / r (where the length of arc is s and the radius is r)
π/4 = s / 12
s = 3π or 9.42 inches
If the question is 5m^2 the answer is 80. And if the question is 5m2 then it is 40
