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Lostsunrise [7]
3 years ago
15

What is the area of the figure 45-45-90 Triangles Find the length of one leg

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0
We can use sine to figure this out. Sine is opposite over hypotenuse. 
So therefore:
sin(45°)=x/24
x=24sin(45)
x=12√2 or about 16.970
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A rectangle or exercise mat has a perimeter of 48 feet the length of the mat Is twice The lift right and solve any questions to
Misha Larkins [42]

Answer:

The equation to determine the length is 4w+2w=48.

The Length of the exercise mat is 16 feet.

Step-by-step explanation:

Given:

Perimeter of Rectangular mat = 48\ ft

Let the length of the mat be denoted by 'l'

And width be denoted by 'w'.

Also Given:

The length of the mat is twice the width of the mat.

So we can say that;

l=2w  ⇒ equation 1

Now we know that;

Perimeter of Rectangle is equal to twice the sum of length and width.

framing in equation form we get;

2(l+w)=48 ⇒ equation 2

Now Substituting equation 1 in equation 2 we get;

2(2w+w)=48

Applying Distributive property we get;

2\times2w+2\times w=48\\\\4w+2w=48

Hence, The equation to determine the length is 4w+2w=48.

On Solving the above equation we get;

4w+2w=48\\\\6w=48

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{48}{6}\\\\w=8\ ft

Now Substituting the value of 'w' in equation 1 we get;

l=2w=2\times8=16\ ft

Hence The Length of the exercise mat is 16 feet.

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