The height of the pile is 150.7 mm, and the volume is V = 6,830,477.5 mm³.
<h3>
How high will be the pile of papers?</h3>
We know that each paper is 0.55mm thick, then if we pile 274 of these, the height of the pile will be:
H = 0.55mm*274 = 150.7mm
Now we want to get the volume of the pile of paper. Remember that for a rectangular prism of height H, width W, and length L, the volume is:
V = H*W*L
In this case, we have:
- H = 150.7mm
- W = 18.5 cm = 185 mm
- L = 24.5 cm = 245 mm
Then the volume is:
V = (150.7mm)*(185 mm)*(245 mm) = 6,830,477.5 mm³
If you want to learn more about volumes:
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Step-by-step explanation:
3x+3² , you might want a second opinion I am no good at math but I tried to work it out to see if I would get it right so don't quote me on this and put it down for an answer get a second opinion please
Answer:

Step-by-step explanation:
Circumference = C = 31.4 ft
We know that,
<h3>C = 2πr</h3>
Where, r is the radius
31.4 = 2(3.14)r
31.4 = 6.28(r)
Divide 6.28 to both sides
31.4/6.28 = r
5 ft. = r
<h3>r = 5 ft.</h3>
Now,
<h3><u>Finding area:</u></h3>
A = πr²
A = (3.14)(5)²
A = (3.14)(25)
<h3>
A = 78.5 ft²</h3>
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Step-by-step explanation:
I wrote the steps in different colour pen so that it would be easier
Hope this is correct and helpful
HAVE A GOOD DAY!
Answer:
Approximately 76.5 mg.
Step-by-step explanation:
Given,
The initial quantity of the Bismuth-210, P = 233 mg,
Also, the rate of decay per day, r = 13 %
Thus, the quantity of the Bismuth-210 after 8 days would be,





