What does p to the power of 5 divided by p to the power of 2 equal?

2 answers:

3 0

P^5 / P^2

The base are equal, so we should to subtracting the powers only

Dividing exponential expressions
P^5 / P^2 = P^(5-2)
:. = P^3

Mama L [17]2 years ago

3 0

Answer:

Step-by-step explanation:

5-2=3

P^5-P^2=P^3

<h3><u>Hope this helps!</u></h3>

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
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\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
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$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
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\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
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$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
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\end{array}\\\\
-----------------------------\\\\
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