280
The 0 is in the ones.
The 8 is in the tens.
The 2 is in the hundreds.
John's Bar 60 km away from Ben's Bar.
Doug's Bar is 40 km away from Kieran's Bar
John's Bar is 10 km nearer to Doug's Bar than Kieran's Bar
If I am to assume that these bar are in a liner position,
Ben's Bar Kieran's Bar John's Bar Doug's Bar
************* 60km*******************
*****************40 km ********************
*********30 km**************
Doug's Bar is 90 km away from Ben's Bar.
Ben to John = 60 km
John to Doug = 30 km
Ben to Doug = 60 + 30 = 90 km.
The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

The second sum is simply the sum of N ones:

So, the final result is

which ends the proof.