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2 years ago

What happens to a horizontal line if you rotate it 90 degrees counterclockwise ?

1 answer:

8 0

It becomes a vertical line, because it is sideways, and if it is rotated 90 degrees, then it becomes vertical
hope this helps, and sorry if im wrong

You might be interested in

Th the mean of the data is set 15 what number is missing<br> 18,16_,9,12,23

Wittaler [7]

Answer:

The missing number on the given data set is 12.

Step-by-step explanation:

Here, the set of data = 18,16_,9,12,23

Let us assume the missing number in the data = m

The mean of the data = 15

Total number of observations = 6

Now, Sum of the data = 18 + 16 + m + 9+ 12+ 23 = 78 + m

Also, $\textrm{ Mean of the given Data} = \frac{\textrm{Sum of all observation in the data}}{\textrm{Total number of observations}}$

$\implies 15 = \frac{78+ m}{6} \\or, 15(6) = 78 + m\\\implies m = 90 -78 = 12$

or, m = 12

Hence, the missing number on the given data set is 12.

3 0

3 years ago

3х – 8y = 19<br> 3х + 5y = — 46

Vadim26 [7]

Answer:

-5

Step-by-step explanation:

multiple the second equation by negative then subtract or add the equations and the answer will be negative 5

4 0

2 years ago

Convert into metre 81Km 30 m

aliya0001 [1]

Answer:81030m

Step-by-step explanation:1km=1000m, 81km=81000+30=81030m

5 0

2 years ago

illey wants to solve the following equations using the method of elimination: y = x – 2 y = 4x – 8 What number should y = x – 2

lbvjy [14]

The second equation has 4x in it t. So to eliminate X, you need to multiply y = x-2 by -4, so the x would become -4x.

7 0

3 years ago

observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

agasfer [191]

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

$2xy =6.....(a)\\\\x-y= 3.....(b)\\\\$

After solve equation (a) we get

$\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\$

After solve equation (b) we get

$\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\$

put the value of x in to equation (x)

$(3+y)y = 3\\$

$y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\$

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

5 0

2 years ago