Problem that would represent

Mathematics

2 answers:

Oksi-84 [34.3K]2 years ago

6 0

$\\ \sf \longmapsto 1+6+(-8)$

Downward motion noted as negative and upward is positive.
Lobby will be 1

$\\ \sf \longmapsto 1+6+(-8)$

$\\ \sf \longmapsto 1+6-8$

$\\ \sf \longmapsto 7-8$

$\\ \sf \longmapsto -1$

option c is correct

mestny [16]2 years ago

5 0

1+6+(-8) = -1 is going to be your answer. aka C

You might be interested in

What is this number in standard form? (3×100)+(1×110)+(4×11,000)

zimovet [89]

Answer:

44410

Step-by-step explanation:

6 0

2 years ago

Solve 2csc^2x-2cscx-1=0 for 0° ≤ x ≤ 360°

umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

$\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ$