Let's first get the coefficients of the numerator: x^4 - 2x^3 + x + 3 = 1, -2, 0, 1, 3
<em>There is no x^2 in the expression, thus, the coefficient for x^2 = 0</em>
Zero of the denominator: x + 3; x = -3
Using synthetic division,
-3 I 1 -2 0 1 3
I_________________
-3 I 1 -2 0 1 3
I_________________
1
-3 I 1 -2 0 1 3
I_____-3___________
1 -5
-3 I 1 -2 0 1 3
I_____-3__15_______
1 -5 15
-3 I 1 -2 0 1 3
I_____-3__15_-45____
1 -5 15 -44
-3 I 1 -2 0 1 3
I_____-3__15_-45____
1 -5 15 -44
-3 I 1 -2 0 1 3
I_____-3__15_-45_132__
1 -5 15 -44 135
The remainder is 135. Which transforms it into 135/x+3.
Thus, the quotient of x^4 - 2x^3 + x + 3 divided by x + 3 is:
Answer:
B. The Huddle Room, by 3 square feet
Step-by-step explanation:
9 * 11 = 99
8 * 12 = 96
99 - 96 = 3
The Huddle Room, by 3 square feet
Hope this helps!
Answer:
90
and
20
i think so ye
Step-by-step explanation:
Answer: 484
===============================================
Work Shown:
First let's compute f(2). We replace every x with 2 and then use PEMDAS to simplify
f(x) = -x^4 + 5x - 4x^2
f(2) = -(2)^4 + 5(2) - 4(2)^2
f(2) = -16 + 5(2) - 4(4)
f(2) = -16 + 10 - 16
f(2) = -6 - 16
f(2) = -22
Then we square this result to find the value of ![[ f(2) ]^2](https://tex.z-dn.net/?f=%5B%20f%282%29%20%5D%5E2)
![f(2) = -22\\\\\left[ f(2) \right]^2 = [ -22 ]^2\\\\\left[ f(2) \right]^2 = 484](https://tex.z-dn.net/?f=f%282%29%20%3D%20-22%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20%5B%20-22%20%5D%5E2%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20484)
Coordinates are written in the form (x,y), x being a certain length along the horizontal x axis and y being a certain height along the vertical y axis. Positive y numbers are in the top half of the plane and negative y numbers are on the bottom. Positive x numbers are on the right side of the plane and negative x numbers are on the left. Therefore, (3,-7) would be 3 across to the right from the origin (where the x and y axes intersect) at (3,0) and 7 downwards from that point to (3,-7).
