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zubka84 [21]
3 years ago
12

The longest side of an acute isosceles triangle is 12 centimeters. Rounded to the nearest tenth, what is the smallest possible l

ength of one of the two congruent sides?
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

The smallest possible length would be 8.5 cm.

Step-by-step explanation:

Since, an acute isosceles triangle having two congruent sides with three acute interior angles,

Given,

The longest side of an acute isosceles triangle is 12 centimeters,

Let x be the side length of the each of the congruent sides,

So, by the property of acute isosceles triangle,

x^2+x^2\geq (12)^2

2x^2\geq 144

x^2\geq 72

\implies x\geq \sqrt{72}=8.48528137424\approx 8.5

Hence, the smallest possible length of one of the two congruent sides is 8.5 cm

liraira [26]3 years ago
6 0
12/sqrt (2)=6/sqrt (2), 8.484cm. Round it up to 8.5cm
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