Answer:
1,3 minimum
1,6 minimum
3,1 maximum
Step-by-step explanation:
Locate the h as x and the k as y for y-k=a(x-h)^2
Answer:
x = -1, y = 2 and z = 1
Step-by-step explanation:
The given system of equations are :
2x - y + 3z= -1 ....(1)
x + 2y - 4z = -1 ......(2)
y – 2z = 0 .....(3)
Equation (3) can be written as :
y = 2z
Use y = 2z in equation (2)
x + 2(2z) - 4z = -1
x + 4z - 4z = -1
x = -1
Put the value of x in equation (1) :
-2 -y +3z = -1
-y+3z = 1 ....(4)
Adding equation (3) and (4)
y-2z+(-y+3z)=1
z = 1
Now put z = 1 in equation (4)
-y+3=1
-y = -2
y = 2
Hence, the values of x,y and z are -1, 2 and 1 respectively.
Because the tell if he number is big or small
What's the equation with x? I can't solve it without knowing where to find x....
M < 7 / 12
(1) < 7 / 12
(1) < 0.583333333 (false statement)
(-1) < 7 / 12
(-1) < 0.583333333 (true statement)
(-9) < 7 / 12
(-9) < 0.583333333 (true statement)
(-5) < 7 / 12
(-5) < 0.583333333 (true statement)
B C D maybe?
