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nlexa [21]
3 years ago
11

Solve the system of equations by elimination. 2x - y + 3z=-1 x + 2y - 4z=-1 y – 2z=0

Mathematics
1 answer:
MrRa [10]3 years ago
6 0

Answer:

x = -1, y = 2 and z = 1

Step-by-step explanation:

The given system of equations are :

2x - y + 3z= -1  ....(1)

x + 2y - 4z = -1  ......(2)

y – 2z = 0  .....(3)

Equation (3) can be written as :

y = 2z

Use y = 2z in equation (2)

x + 2(2z) - 4z = -1

x + 4z - 4z = -1

x = -1

Put the value of x in equation (1) :

-2 -y +3z = -1

-y+3z = 1 ....(4)

Adding equation (3) and (4)

y-2z+(-y+3z)=1

z = 1

Now put z = 1 in equation (4)

-y+3=1

-y = -2

y = 2

Hence, the values of x,y and z are -1, 2 and 1 respectively.

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<h2><u>Problem Solving</u>:-</h2>

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<h2><u>Solution</u>:-</h2>

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\sf{\rightarrow{d =  kt}}

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<h2><u>Answer</u>:-</h2>
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