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3 years ago

Find the equation of a line with the given points.(put your answers in the form y=mx+b)(6,2)(5,5)

Mathematics

2 answers:

Nesterboy [21]3 years ago

6 0

The slope-intercept form: y= mx + b

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (6, 2) and (5, 5). Substitute:

$m=\dfrac{5-2}{5-6}=\dfrac{3}{-1}=-3$

Therefore we have y = -3x + b.

Put the coordinates of the point (5, 5) to the equation:

5 = -3(5) + b

5 = -15 + b <em>add 15 to both sides</em>

20 = b

<h3>Answer: y = -3x + 20</h3>

igomit [66]3 years ago

5 0

Answer:

y = -3x + 20

Step-by-step explanation:

(a) Slope

The <em>point-slope formula</em> for a straight line is

y₂ - y₁ = m(x₂ - x₁) Insert the points

2 - 5 = m(6 - 5)

-3 = m×1

m = -3

=====

(b) y-intercept

y₂ - y₁ = m(x₂ - x₁)

y₂ - 5 = -3(x₂ - 5) Remove parentheses

y₂ - 5 = -3x₂ - 15 Add 5 to each side

y = -3x + 20

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Answer:

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Step-by-step explanation:

Given:

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3 years ago

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algol13

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3 years ago

A given line has the equation 2x + 12y = −1. What is the equation, in slope-intercept form, of the line that is perpendicular to

VikaD [51]

Answer:

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Step-by-step explanation:

The equation of a line in slope- interceot form is

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