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3 years ago

6

which of the following indicates that triangle QRS and triangle TUV are similar? Btw I need a valid step-by-step on how you do t

his, if not I'll report your answer, and assume you're doing it for the points!!

1 answer:

Korvikt [17]3 years ago

7 0

Answer:

third option.

∼ means similar

≅ means congruent

≈ means approximate

= means equal

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16 points PLZ HELP which equation represents the function graphed on the coordinate plane

maksim [4K]

It’s the second one. The one that is g(x) = |x + 3| — 1

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3 years ago

Read 2 more answers

Samuel is solving the equation 3(x - 1) + 4 = 2 - (x + 3). Which equivalent equations might Samuel use? Select the TWO correct a

mote1985 [20]

A= 3, and 4. (c & d)

1. Solve the Equation: $3(x - 1) + 4 = 2 - (x + 3)\\$ , to get

------------------------------------------

1a. Use the distributive property to multiply 3 by x−1.

$3x−3+4=2−(x+3)$

1b. Add −3 and 4 to get 1.

$3x+1=2−(x+3)$

1c. To find the opposite of x+3, find the opposite of each term.

$3x+1=2−x−3$

1d. Subtract 3 from 2 to get −1.

$3x+1=−1−x$

1e. Add x to both sides.

$3x+1+x=−1$

1f. Combine 3x and x to get 4x.

$4x+1=−1$

1g. Subtract 1 from both sides.

$4x=−1−1$

1h. Subtract 1 from −1 to get −2.

$4x=−2$

1i. Divide both sides by 4.

$x=4−2$

1j. Reduce the fraction 4−2=−0.5 to lowest terms by extracting and canceling out 2.

$x=−21$ or x = -21

-------------------------------------

Now that you know the answers, solve the others:

2. A= 1, so this is wrong. How I solved it is shown below:

-----------------------------------

1a. Add −3 and 4 to get 1.

3x+1=2−x+3

1b. Add 2 and 3 to get 5.

3x+1=5−x

1c. Add x to both sides.

3x+1+x=5

1d. Combine 3x and x to get 4x.

4x+1=5

1e. Subtract 1 from both sides.

4x=5−1

1f. Subtract 1 from 5 to get 4.

4x=4

1g.Divide both sides by 4.

x=44

1h. Divide 4 by 4 to get 1.

x=1

----------------------------

3. A= .5, so it is Correct. Work below

-----------------------------

3a. Add x to both sides.

$3x+3+x=5$

3b. Combine 3x and x to get 4x.

$4x+3=5$

3c. Subtract 3 from both sides.

$4x=5−3$

3d. Subtract 3 from 5 to get 2.

$4x=2$

3e. Divide both sides by 4.

$x=42$

3f. Reduce the fraction 42=0.5 to lowest terms by extracting and canceling out 2.

$x=21$ (A = 1/2 or .5)

-----------------------------

4. A= .5, so it is correct. Work below. Now we have our 2, so we don't need to do it again.

-------------------------------

4a. Add −1 and 4 to get 3.

$3x+3=2−x+3$

4b. Add 2 and 3 to get 5.

$3x+3=5−x$

4c. Add x to both sides.

$3x+3+x=5$

4d. Combine 3x and x to get 4x.

$4x+3=5$

4e. Subtract 3 from both sides.

$4x=5−3$

4f. Subtract 3 from 5 to get 2.

$4x=2$

4g. Divide both sides by 4.

$x=\frac{2}{4}$

4h. Reduce the fraction 42=0.5 to lowest terms by extracting and canceling out 2.

$x=\frac{1}{2}$

7 0

3 years ago

How do i find the circumference of a circle? If I use a 3 as an estimate of pie and the circle is 10 mm across

Llana [10]

If you're using pie it would be

2* $\pi$ *5 because the radius is half of the diameter.

But since you're using three it's

2*3*5

If it helps remember: Twinkle twinkle little star, circumference equals 2 pi r

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2 years ago

Help I don't understand,

antoniya [11.8K]

In the drawing the base picture shows two squares on next to each other

The side picture shows three squares, one next to other and one above the square that right most.

The front picture shows two one square above other square.

The three dimensional figure that corresponds to those three view is a set of three boxes two in the base and one above one of the boxes of the base.

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3 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

Aleonysh [2.5K]

Answer:

t=5.18 minute

Step-by-step explanation:

Using Newton's law of cooling

$\frac{dT}{dt}=-k(T-T_{s})$

T is temperature of a cup of coffee at any time t $T_{s}$ , is the temperature of the surrounding and k is a constant of proportionality in this negative because temperature is decreasing.

$T(0)=190\\T(1)=170\\T_{s}=66$

$\frac{dT}{dt}=-k(T-T_{s})\\\frac{dT}{(T-T_{s})}=-k*dt\\\int\limits {\frac{1}{T-T_{s} } } \, dT=-\int\limits {k} \, dt\\ln(T-T_{s})=k*t+C\\e*ln(T-T_{s})=e^{k*t+C} \\T-T_{s}=e^{k*t}*e^{C}\\e^{C}=C\\T-T_{s}=e^{k*t}*C\\T=T_{s}+e^{k*t}*C$

To find constant knowing the time and the temperature the first step of the change of energy in cup of coffee

$T=T_{s} +e^{-k*t}*C\\ C=190-66=124\\170=66+124*e^{-k*2}\\ 170-66=124*e^{-k*2}\\ln(\frac{104}{124})=ln*e^{-k*2}\\-0.175=-k*2\\k=0.08794$

Now using the constant of decreasing can find the time to be a 145 temperature the cup of coffee

$145=66+124*e^{-k*t} \\145-66=124*^{-0.087*t}$

$ln(0.637)=ln*e(-0.087*t)\\-0.45=-0.087*t\\t=5.18minutes$

4 0

3 years ago