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Sedaia [141]
3 years ago
12

What is the square root of 24

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0
The square root of 24 is = 4.898979485566357
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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Can I get some help plz?
Anika [276]

Answer:

X=20 degree

Step-by-step explanation:

∆A+∆D+∆O=180

2x+10+2x+90=180

collect like terms

2x+2x=180-100

4x=80

(4x)/4=(80)/4

x=20 degree

6 0
2 years ago
Read 2 more answers
The scale drawing of a backyard includes a tennis court 10cm x 5.5cm. If the drawing has a scale
Natasha2012 [34]

Step-by-step explanation:

2.5 m = 250 cm

so, the scale factor is 1/250

that means the tennis court is in reality

10×250cm × 5.5×250cm = 2500 × 1375 = 3,437,500 cm²

1 m² = 100×100 = 10,000 cm²

so,

3,437,500 cm² = 343.75 m²

5 0
2 years ago
In the diagram below, transversal t intersects parallel lines I and m.
Black_prince [1.1K]

Step-by-step explanation:

x+10=116

x=116-110

=106

x=106

6 0
2 years ago
Please I really need help:
Kobotan [32]
Hi there

The answer is
b.) y=8,000(1.14)^x

Good luck!
6 0
3 years ago
Read 2 more answers
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