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2 years ago

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What is the square root of 24

1 answer:

RideAnS [48]2 years ago

6 0

The square root of 24 is = 4.898979485566357

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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

tankabanditka [31]

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials $3x^5y-2x^3y^4-7xy^3$ and $-8x^5y+2x^3y^4+xy^3$

<h3>Now sum the given polynomials :</h3>

$3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3$

$=-5x^5y+0-6xy^3$

$=-5x^5y-6xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3$

In the simplified <u>sum of the polynomials</u> $-5x^5y-6xy^3$ we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

$3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3$

$=11x^5y-4x^3y^4-8xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3$

In the simplified <u>difference of polynomials</u> $11x^5y-4x^3y^4-8xy^3$ we have <u>the degree is 7</u>

Therefore the option " The sum has degree of 6 , but the difference has a degree of 7 " is correct

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2 years ago

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igomit [66]

3/5 > 4/7 > 5/9. This is the answer when the fractions are increasing.

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2 years ago

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Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

$d=vt-\dfrac{1}{2}at^2$

First subtract $vt$ from both sides:

$d-vt--\dfrac{1}{2}at^2$

and multiply the equation by -1:

$vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)$

Now multiply (1) by 2:

$2(vt-d)=at^2\ \ \ \ \ (2)$

At last, divide by $a$

$t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)$

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sesenic [268]

I worked this out, and the answer is B.) 14x+6
Hope it helped! :3

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