<img src="https://tex.z-dn.net/?f=5%5Csqrt%7B2%7D%20%2F%20%5Csqrt%7B18" id="TexFormula1" title="5\sqrt{2} / \sqrt{18" alt="5\sqr

Katyanochek1 [597]

3 years ago

t{2} / \sqrt{18" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

crimeas [40]3 years ago

8 0

Answer:

Step-by-step explanation:

what is the question

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KatRina [158]

Answer:

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Radium-228 has a half-life of 5.75 years. What is the decay rate for radium-228?

artcher [175]

Decay rate for Radium-228 is 0.01205

Step-by-step explanation:

The half life of radium-228 is 5.75 years. We need to find the decay rate for radium.

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$ln\frac{N_o}{N_t}=-\lambda t$

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N_t = amount of radioactive particles are time (t)

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Putting values in formula and solving:

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$ln(0.5)=-\lambda *5.75\\-\lambda=\frac{ln(0.5)}{5.75}\\-\lambda=\frac{-0.69}{5.75}\\-\lambda=-0.1205\\\lambda=0.1205$

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Answer:

Step-by-step explanation:

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