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Tatiana [17]
4 years ago
13

Anderson had $42.75. He spent $13.25 on a DVD and $17.75 on a gift.

Mathematics
2 answers:
V125BC [204]4 years ago
8 0

Yes. He would have enough left to buy lunch. Answer:

Step-by-step explanation: $13.25 + $17.75=$31

$31 + 10.25=$41.25

timurjin [86]4 years ago
5 0

Answer:

Yes he would! He had $11.75 after he bought the DVD and the gift

Step-by-step explanation:

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In a cricket match, Rajat scored thrice as many runs as Devansh.
Rina8888 [55]

Answer:

let jivesh score x runs so rajat scores 3x runs

total runs = 300-8 = 292 runs

so x+3x = 292

4x = 292

x = 292/4

x = 73

so jivesh score 72 runs and rajat scores 216 runs

Step-by-step explanation:

5 0
3 years ago
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* Use order of operations to solve the following.
Bingel [31]
The answer is 100 if that 5 and 2 is separate
3 0
3 years ago
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The length width and height of a rectangular solid are 8,4,1 respectively what is the length of the longest line segment whose e
LUCKY_DIMON [66]

Answer:

9 units

Step-by-step explanation:

Given

Length = 8

Width = 4

Height = 1

Required

Determine the length of the longest segment

To do this, we use:

Longest = \sqrt{Length^2 + Width^2 + Height^2}

So, we have:

Longest = \sqrt{8^2 + 4^2 + 1^2}

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Longest = \sqrt{81}

Take positive square root

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3 0
3 years ago
See the question attached. Please help
Lelu [443]

Answer:

1) 36

2) 190

3) 72 units

Step-by-step explanation:

1)  2x4 = 8 units area for rectangle

(4-2) x4 /2 = 4 units

6 x 4 = 24 units

8 + 4 + 24 = 36

2) 3 x 10 / 2 = 15 units

   5 x 10 /2 = 25 units

   15 x 10 = 150 units

   150 + 25 + 15 = 190 units

3) 6 x 3 / 2 = 9 units

   6 x 9 = 54 units

   6 x 3 / 2 = 9 units

9 + 9 + 54 = 18 + 54 = 72 units

3 0
2 years ago
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I need to know what -(6h + 7) + 8 = -19 is
melisa1 [442]

Answer:

10/3

Step-by-step explanation:

-1(6h + 7) = -6h - 7

-6h - 7 + 8 = -6h + 1

-6h + 1 = -19

        -1     -1 <em>- Subtract 1 from both sides.</em>

-6h = -20

-6        -6<em> - Divide both sides by negative 6</em>

h = 10/3

4 0
3 years ago
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