Ask question

Ask question

All categories

3 years ago

13

Ryan made a cd of his favorite songs. There are 42 minutes of time on Cd. He records 14 songs. What is the average length of eac

h song?

2 answers:

postnew [5]3 years ago

7 0

The average song length is 3 minutes (divide 42 and 14)

solmaris [256]3 years ago

6 0

The average length of each song is 3 minutes . The steps to do that is 42 minutes divided to 14 songs and you have the answer is 3 .

You might be interested in

Calculus help ASAP!!!

anastassius [24]

Let $c\in(0,\infty)$ . Then the definite integral can be split up at $t=c$ so that

$\displaystyle F(x)=\int_{t=2x}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=\int_{t=2x}^{t=c}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=-\int_{t=c}^{t=2x}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$

Now take the derivative. By the fundamental theorem of calculus, you have

$\displaystyle\frac{\mathrm dF}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\left[\int_{t=c}^{t=5x}\frac{\mathrm dt}t-\int_{t=c}^{t=2x}\frac{\mathrm dt}t\right]$
$=\displaystyle\frac1{5x}\dfrac{\mathrm d}{\mathrm dx}[5x]-\frac1{2x}\dfrac{\mathrm d}{\mathrm dx}[2x]$
$=\dfrac5{5x}-\dfrac2{2x}$
$=\dfrac1x-\dfrac1x$
$=0$

Then integrating with respect to $x$ , we recover $F(x)$ and find that

$\displaystyle\int\dfrac{\mathrm dF}{\mathrm dx}\,\mathrm dx=\int0\,\mathrm dx$
$F(x)=C$

where $C$ is an arbitrary constant.

7 0

3 years ago

I have a question please answer it.

Tems11 [23]

Answer:

A or B Ma'am or sir. Have an amazing day and good luck!!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Donna is putting down tile on her outdoor deck. The shape of her deck is shown below. Each unit on the coordinate plane represen

Marysya12 [62]

Where’s is the link??

4 0

3 years ago

For questions 10 – 11, if l ||m, find the values of x and y

iogann1982 [59]

Answer:

10). x = 16

y = 10

11). x = 24

y = 19

Step-by-step explanation:

10). Since l ║ m and a line is transverse intersecting these parallel lines at two distinct points.

Two angles having measures (8x - 14)° and (5x + 34)°are the alternate exterior angles.

Since alternate interior angles are equal in measures.

Therefore, (8x - 14) = (5x + 34)

8x - 5x = 34 + 14

3x = 48

x = 16

Measure of angle (8x - 14)° = 8×16 - 14

= 128 - 14

= 114°

Sum of supplementary angles = 180°

Therefore, (8x - 14)° + (5y + 16) = 180°

114° + (5y + 16)°= 180°

5y = 180 - 130

y = 10

Therefore, x = 16 and y = 10

11). m∠BAC = (5y - 23)°

m∠ACB = 47°

m∠ABC = (2x + 13)°

Since these angles are the angles of a triangle,

(5y - 23)° + 47° + (2x + 13)° = 180°

5y + 2x = 180 - 37

2x + 5y = 143 ------(1)

Lines l ║ m and AC is a transverse,

3x = 5y - 23 [Exterior corresponding angles]

3x - 5y = -23 -----(2)

By adding equation (1) and (2)

(2x + 5y) + (3x - 5y) = 143 - 23

5x = 120

x = 24

From equation (1),

2(24) + 5y = 143

5y = 143 - 48

5y = 95

y = 19

Therefore, x = 24 and y = 19

4 0

3 years ago

How do I find the surface area and volume of the larger figure using that of the smaller figure?

dalvyx [7]

We know that
scale factor=1/8

volume smaller figure=[scale factor]³*volume larger figure
so
volume larger figure=volume smaller figure/[scale factor]³
volume smaller figure=7 km³
volume larger figure=7/[1/8]³----> 7/(1/512)---> 7*512---> 3584 km³

the answer Part a) is
the volume of the larger figure is 3584 km³

surface area smaller figure=[scale factor]²*surface area larger figure
surface area larger figure=surface area smaller figure/[scale factor]²
surface area smaller figure=9 km²
surface area larger figure=9/[1/8]²----> 9/(1/64)---> 9*64---> 576 km²

the answer part b) is
the surface area of the larger figure is 576 km²

4 0

3 years ago