<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
17; 22; 27; 32
the terms increase by 5 each time
17 + 5 = 22 (the second term)
17 + 5 * 2 = 27 (third term)
So to get to the 52nd term, we have to add 5* 51 = 255 to 17
17 + 255 = 272
Step-by-step explanation:
The answer is -2/3 from the solution above
Estimate 285 as 300 and 11 as 10 so
we have 300 / 10 = 30
Its C
Answer:
maybe 250%?
Step-by-step explanation:
Just a guess! hope i helped somehow<3
