Is the answer a, b, c, or d?

In a fish tank, there are 24 goldfish, 2 angel fish, and 5 guppies. if a fish is selected at random, find the probability that i

Artist 52 [7]

There are a total of 31 fish in the tank. Therefore, the probability of it being a goldfish is 24/31 or about 77.4%, since there are 24 goldfish. The probability of it being an angel fish is 2/31 or about 6.45%, for the same reason as before.

3 0

3 years ago

Water is being pumped into a conical tank that is 8 feet tall and has a diameter of 10 feet. If the water is being pumped in at

Deffense [45]

The rate of change of the depth of water in the tank when the tank is half

filled can be found using chain rule of differentiation.

When the tank is half filled, the depth of the water is changing at 1.213 ×

10⁻² ft.³/hour.

Reasons:

The given parameter are;

Height of the conical tank, h = 8 feet

Diameter of the conical tank, d = 10 feet

Rate at which water is being pumped into the tank, = 3/5 ft.³/hr.

Required:

The rate at which the depth of the water in the tank is changing when the

tank is half full.

Solution:

The radius of the tank, r = d ÷ 2

∴ r = 10 ft. ÷ 2 = 5 ft.

Using similar triangles, we have;

$\dfrac{r}{h} = \dfrac{5}{8}$

The volume of the tank is therefore;

$V = \mathbf{\dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h}$

$r = \dfrac{5}{8} \times h$

Therefore;

$V = \dfrac{1}{3} \cdot \pi \cdot \left( \dfrac{5}{8} \times h\right)^2 \cdot h = \dfrac{25 \cdot h^3 \cdot \pi}{192}$

By chain rule of differentiation, we have;

$\dfrac{dV}{dt} = \mathbf{\dfrac{dV}{dh} \cdot \dfrac{dh}{dt}}$

$\dfrac{dV}{dh}=\dfrac{d}{h} \left( \dfrac{25 \cdot h^3 \cdot \pi}{192} \right) = \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64}}$

$\dfrac{dV}{dt} = \dfrac{3}{5} \ ft.^3/hour$

Which gives;

$\dfrac{3}{5} = \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64} \times \dfrac{dh}{dt}}$

When the tank is half filled, we have;

$V_{1/2} = \dfrac{1}{2} \times \dfrac{1}{3} \times \pi \times 5^2 \times 8 =\mathbf{ \dfrac{25 \cdot h^3 \cdot \pi}{ 192}}$

Solving gives;

h³ = 256

h = ∛256

$\dfrac{3}{5} \times \dfrac{64}{25 \cdot h^2 \cdot \pi} = \dfrac{dh}{dt}$

Which gives;

$\dfrac{dh}{dt} = \dfrac{3}{5} \times \dfrac{64}{25 \cdot (\sqrt[3]{256}) ^2 \cdot \pi} \approx \mathbf{1.213\times 10^{-2}}$

When the tank is half filled, the depth of the water is changing at 1.213 × 10⁻² ft.³/hour.

Learn more here:

brainly.com/question/9168560

6 0

2 years ago

1. Vladimir Hirsch worked these hours last week: Monday, 8 hours; Tuesday, 7 hours;

olga2289 [7]

Answer: he worked 32 hours and make $512

4 0

3 years ago

Which is the better deal?

andreev551 [17]

48 oz?

Step-by-step explanation:

I don't know if you are just asking or what not but I belive it is 48 ozs but I could be wrong

8 0

3 years ago

Read 2 more answers

Solve for x: −12 > −36 − 8x

Mars2501 [29]

With these equations what you do to one side you have to do to the other and if you divide using a negative such as when you divide -8 you switch the greater than sign to the opposite direction so add 36 and it will cancel and add it to negative 12 which will actually be subtracting because 12 is negative and then you divide negative 8 by both sides

6 0

3 years ago