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1 year ago

In the diagram below, O is circumscribed about quadrilateral DEFG. What is

Mathematics

1 answer:

Nimfa-mama [501]1 year ago

8 0

Since O is circumscribed about quadrilateral DEFG, the value of x is equal to: D. 68°.

<h3>What is a supplementary angle?</h3>

A supplementary angle can be defined as two (2) angles or arc whose sum is always equal to 180 degrees. Mathematically, a supplementary angle can be calculated as follows:

Q + R = 180°.

In Geometry, the opposite angles of any cyclic quadrilateral that is inscribed inside a circle always form a supplementary angle. Thus, we would determine the value of x by using the mathematical expression above:

x + 112° = 180°

x = 180° - 112°

x = 68°

Read more on supplementary angle here: brainly.com/question/12542846

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HELP ASAP!! 100 POINTS!!<br><br> describe how you would plot the point (-4, 3)

fredd [130]

Answer:

Hi!

First you would start at -4 on the x-axis, then you would move up 3 spaces and put your point there.

The x-axis is the horizontal line, and the y-axis is the vertical line.

I hope this helps you!

6 0

3 years ago

Read 2 more answers

Pls help I don't understand:

sineoko [7]

Answer:

Part a) $T(d)=2d+30$

Part b) $T(6)=42\ minutes$

Step-by-step explanation:

Part a) Write an equation for T (d)

Let

d ----> the number of days

T ---> the time in minutes of the treadmill

we know that

The linear equation in slope intercept form is equal to

$T=md+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit rate is

$m=2\ \frac{minutes}{day}$

The y-intercept or initial value is

$b=30\ minutes$

substitute

$T(d)=2d+30$

Part b) Find T (6), the minutes he will spend on the treadmill on day 6

For d=6

substitute in the equation and solve for T

$T(6)=2(6)+30$

$T(6)=42\ minutes$

8 0

2 years ago

to avoid a large shallow reef a ship set a course from point a and traveled 24 miles east to point b . the ship them turn and tr

Sever21 [200]

First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi

Next, we are going to use the Pythagorean theorem to find the distance from $a$ to $c$ :
$d^2=24^2+33^2$
$d^2=576+1089$
d^2=1665
$d= \sqrt{1665}$
$d=40.8$ mi

Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi

We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>