Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.
2 answers:
Answer:
Table for y = 2|x-4| + 3 on domain {2,3,4,5,6} is given as:
x y
2 2|x-4| + 3 = 2|2-4| + 3 = 7
3 2|x-4| + 3 = 2|3-4| + 3 = 5
4 2|x-4| + 3 = 2|4-4| + 3 = 3
5 2|x-4| + 3 = 2|5-4| + 3 = 5
6 2|x-4| + 3 = 2|6-4| + 3 = 7
The graph of the absolute value function y = 2|x-4| + 3 for the given domain is attached.
Step-by-step explanation:
The absolute value parent function, written as function(x) = | x |, is defined as:
|x| = x and |-x| = x
In our case;
For x = 2
y = 2|x-4| + 3
= 2|2-4| + 3
= 2|-2| + 3
= 2*2 + 3
= 4 + 3
= 7
Similarly, for all other values of x in the given domain, value of y can be calculated.
Answer:
<h2>In the attachment.</h2>Step-by-step explanation:
Put each value of x from the set {2, 3, 4, 5, 6}
to the equation y = 2|x - 4| + 3:
x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)
x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)
x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)
x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)
x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)
Mark the points in the coordinates system.
The domain is only five numbers, therefore the graph of this function is only five points.
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