r/q= sin y
I got sin y,
or option one
Hope this helps ;3
12/84 = 1/7 ≈ 0.14
The discount rate was 14%
If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes
P1V1 = P2V2 --> (41)(16) = P2 (4)
--> P2 (4) = 656
P2 = 656/4 = 164 kPa
Answer: The blue whale's weight is 150 times heavier than the narwhal's weight.
Step-by-step explanation:
Given: Weight of Blue whale = 
Weight of Narwhal = 
Number of times blue whale's weight is heavier than the narwhal's weight = 
![=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B3%5Ctimes10%5E5%7D%7B2%5Ctimes10%5E3%7D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E%7B5-3%7D%5C%20%5C%20%5C%20%5B%5Cdfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E2%5C%5C%5C%5C%3D1.5%5Ctimes100%3D150)
Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.
2
3x. + 63x + 9x + 189
Step-by-step explanation:
<em>Use</em><em> </em><em>distributive</em><em> </em><em>law</em><em>,</em><em> </em><em>in</em><em> </em><em>other</em><em> </em><em>words</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em>
