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3 years ago

A rectangle is formed by placing two identical squares side by side

Mathematics

1 answer:

julsineya [31]3 years ago

4 0

Answer:

200

Step-by-step explanation:

If there are 2 squares next to eachother with the same area, then their perimeter is 6*sidelength.

60 = 6*sidelength

10 = sidelength

Square the sidelength to find the area of the square. 10^2 = 100

Multiply that by 2 to find the area of the rectangle. 100*2 =

200

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a total of 35 students are going to a field trip to NASA'S Johnson space center in houston,texas if there needs to be one adult

Trava [24]

Answer:

at least 5

Step-by-step explanation:

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3 years ago

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What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x/4+5 ?

worty [1.4K]

Answer:

y = -4x+15

Step-by-step explanation:

y=x/4+5 may be presented as y = 1/4 x + 5, where a=1/4, b=5

swapping numerator and denominator and inserting an opposite sign in a=1/4, we have:

1/4 --------> 4/1 -------> -4/1 = -4

y = -4x+n

Point (2,7) means that x=2, y=7 substitute it to the equation y=-4x+n, calculate "n":

7=-4*2+n ------> 7=-8+n -------> 7+8 = n -------> 15=n

substituting n=15 to the equation y=-4x+n, we get finally y=-4x+15

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3 years ago

2 pyramids have a volume of 8 and the larger volume is 343<br> what is the scale factor

Mice21 [21]

Answer

i think its 42.875

step-by-step explanation:

divide 343 by 8 i think

7 0

3 years ago

Solve x please 2x/3=4

Semenov [28]

Multiply both siase of equation by 3
2x*3/3=4*3
2x=12
devide by 2
2x:2=12:2
x=6
Answer: x=6

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3 years ago

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Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago