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Sergio [31]
3 years ago
5

Which of the following is the solution set for -3t + 11 > 20?

Mathematics
2 answers:
Lelechka [254]3 years ago
7 0

Answer: C. t < -3

<em>Hope this helps!</em>

vodka [1.7K]3 years ago
6 0

Answer: C. t < -3

Because i made a 100 on my test

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The issue of corporate tax reform has been cause for much debate in the United States. Among those in the legislature, 27% are R
Ilia_Sergeevich [38]

Answer:

The probability Democrat is selected given that this member favors some type of corporate tax reform is 0.6309.

Step-by-step explanation:

Let us suppose that,

R = Republicans

D = Democrats

I = Independents.

X = a member favors some type of corporate tax reform.

The information provided is:

P (R) = 0.27

P (D) = 0.56

P (I) = 0.17

P (X|R) = 0.34

P (X|D) = 0.41

P (X|I) = 0.25.

Compute the probability that a randomly selected member favors some type of corporate tax reform as follows:

P(X)=P(X|R)P(R)+P(X|D)P(D)+P(X|I)P(I)\\= (0.34\times0.27)+(0.41\times0.56)+(0.25\times0.17)\\=0.3639

The probability that a randomly selected member favors some type of corporate tax reform is P (X) = 0.3639.

Compute the probability Democrat is selected given that this member favors some type of corporate tax reform as follows:

P(D|X)=\frac{P(X|D)P(D)}{P(X)} =\frac{0.41\times0.56}{0.3639}=0.6309

Thus, the probability Democrat is selected given that this member favors some type of corporate tax reform is 0.6309.

5 0
3 years ago
The differences between the data points and the estimated regression line are called the
pashok25 [27]
<span>Linear regression is a method of finding the linear equation that comes closest to fitting a collection of data points.
</span>The better the choice of line, the closer the predicted values will be to the observed values.
The differences between the data pints (observed values) and the estimated (pedicted) regression line is called  the <span>residue.
</span>Residue = Observed Value -<span> Predicted Value</span>
8 0
3 years ago
Several students and adult chaperones are going on a field trip to the theater. Each student ticket cost $2 and each adult ticke
stiks02 [169]
<span>The answer to this question would be: A. the number of adults
</span>
In this question, there are 4 times as many students as adults going on the trip. If we put it into a function where s= student and a=adult, then we could get one equation:<span>
1. s=4a
</span><span>
Each student ticket cost $2 and each adult ticket cost $4. The total cost of the trip is $144. We also can get one equation for this
2. 2s+ 4a= 144

If you put the first equation into the second, you will get:
</span>2s+4a= 144
2(4a)+4a= 144

The function is already similar with <span>2(4x)+4x but it uses a instead of x. Then x = a = number of adult</span>
6 0
3 years ago
Read 2 more answers
First to answer correctly gets brainliest
Readme [11.4K]

Answer:

240 \leq 12.5p + 65

14 \leq\\ p

Step-by-step explanation:

I'll explain the equation in different parts

12.5p - Since the number of times he visits is unknown, it has to be a variable. With each visit, however, he earns 12.5 points.

65 - This is a set value that remains constant

240 \leq\\ - Since he needs AT LEAST 240 points, he needs 240 points or more to get his free ticket

As for solving the equation just use properties of equality

240 \leq 12.5p + 65

175 \leq 12.5p

14 \leq\\ p

7 0
3 years ago
The value of a weight vector is given as (w1=3, w2=-2, w0=1) for a linear model with soft threshold (sigmoid) function f(x).
dolphi86 [110]

Answer:

Please see explanation for the answer. The code is written in python and is as given below:

Step-by-step explanation:

The solution is obtained on the Python with the following code

import matplotlib.pyplot as plotter

import numpy as npy

x_s = npy.linspace(-5,5,100)  #Defining a linear sample space with boundaries as -5 to 5 and 100 as number of samples.

def sigmo(z):return 1/(1 + npy.exp(-z)) #Defining sigmoid function for the f(x).

plotter.plot(x_s, sigmo(x_s))

plotter.plot([-5,5],[.5,.5])

plotter.xlabel("z")

plotter.ylabel("sigmoid(z)")

plotter.show()

8 0
3 years ago
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