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Cerrena [4.2K]
3 years ago
14

Which is a graph for the inequality m<(or equal to)-2?

Mathematics
1 answer:
brilliants [131]3 years ago
5 0

Answer:

cool

Step-by-step explanation:

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You and your friend are selling subscriptions for a fundraiser. After w weeks you have sold (3w+4) subscrions and your friend ha
soldier1979 [14.2K]
3w + 4 - 5w + 1

-2w + 5
6 0
3 years ago
What is the greatest common factor of 16ab3 + 4a2b + 8ab ?
ziro4ka [17]

Answer:

2ab(3b^2+2a+4)

Step-by-step explanation:

6ab^3 + 4a^2b + 8ab

2*3*a*b*b^2 +2*2*a*a*b +2*2*2*a*b

Factor out the common terms

2ab( 3*b^2 +2*a +2*2)

2ab(3b^2+2a+4)

5 0
3 years ago
How do I solve for x?
notka56 [123]
Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


7 0
3 years ago
Simplify (3n – 2m)2 = ?
Bumek [7]
If you mean (3n-2m)^2 then the answer is
9n^2-12mn+4m^2
So B
4 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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