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drek231 [11]
3 years ago
8

jordan is chopping wood for the winter. for 10 days on a row he follows the same process: in the morning he chops 20 pieces of w

ood and in the evening he chops an additional 30 pieces of wood on the 11th day jordan chops only 5 pices of wood write a numerical expression with parentheses for the total number of pieces of wood jordan chopped. (do not simplify your expression)
Mathematics
1 answer:
Grace [21]2 years ago
5 0

(20 + 30) \times 10 + 5
I'm 90% sure that's right, sorry if I'm wrong :/
You might be interested in
Find ordered pair that is solution for liner equation 4x - 5y=20
Nat2105 [25]

Answer:

(0,-4) (5,0)

Step-by-step explanation:

4x-5y=20

First, we must put the equation into slope intercept form: y= mx+b

5y=4x-20=y=4/5x-4

The y intercept, by definition, is b. In this scenario, b is -4.

One ordered pair that works is (0,-4).

Also, we can find the ordered pair for the x intercept. By definition, the x intercept is the value of x when y equals zero. hence, we substitute 0 for y and then we can find an ordered pair that works and solve for x!:

  1. 0=4/5(x)-4= 4=4/5x
  2. 4x=20
  3. x=5

Therefore, (5,0) works as well!

3 0
2 years ago
A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}

We have to find the rate of increase of length.

Area of rectangle =

A = l\times w

Differentiating we get,

\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l

Putting values, we get,

8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0
2 years ago
George had $15. He bought a shirt on sale for $6. Which decimal is equivalent to the fraction of money George has left
Over [174]

Answer:

.9

Step-by-step explanation:

15-6=9

3 0
3 years ago
Is the following function exponential?
frutty [35]

Answer:

Answer: yes

Step-by-step explanation:

i took the test

7 0
3 years ago
Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees0° and standard deviation of 1.00d
nikitadnepr [17]

For this question, we assume that 2.5% of the thermometers are rejected at both sides of the distribution because they have readings that are too low or too high.

Answer:

The "two readings that are cutoff values separating the rejected thermometers from the others" are -1.96 Celsius degrees (below which 2.5% of the readings are too low) and 1.96 Celsius degrees (above which 2.5% of the readings are too high).

Step-by-step explanation:

We can solve this question using the <em>standard normal distribution</em>. This is a normal distribution with mean that equals 0, \\ \mu = 0, and standard deviation that equals 1, \\ \sigma = 1.

And because of using the <em>standard normal distribution</em>, we are going to take into account the following relevant concepts:

  • <em>Standardized scores or z-scores</em>, which we can consider as the <em>distance from the mean</em> in <em>standard deviations units</em>, and the formula for them is as follows:

\\ Z = \frac{X - \mu}{\sigma} [1]

A positive value indicates that the possible raw value X is <em>above</em> \\ \mu, and a negative that the possible raw value X is <em>below</em> the mean.

  • <em>The [cumulative] standard normal table:</em> there exists a table where all these values correspond to a probability, and we can apply it for every possible normally distributed data as well as we first standardize the possible raw values for <em>X</em> using [1]. This table is called the <em>standard normal table</em>, and it is available in all Statistics books or on the Internet.

From the question, we have the following information about the readings on the thermometers, which is a normally distributed random variable:

  • Its <em>mean</em>, \\ \mu = 0 Celsius degrees.
  • Its <em>standard deviation</em>, \\ \sigma = 1.00 Celsius degrees.

It coincides with the <em>parameters</em> of the <em>standard normal distribution</em>, and we can find probabilities accordingly.

It is important to mention that the readings that are too low or too high in the normal distribution are at both extremes of it, one of them with values below the mean, \\ \mu, and the other with values above it.

In this case, we need to find:

  • First, the value <em>below</em> which is 2.5% of the lowest values of the distribution, and
  • Second, the value <em>above</em> which is 2.5% of the highest values of the distribution.

Here, we can take advantage of the <em>symmetry</em> of the normal or Gaussian distributions. In this case, the value for the 2.5% of the lowest and highest values is the <em>same in absolute value</em>, but one is negative (that one below the mean, \\ \mu) and the other is positive (that above the mean).

Solving the Question

<em>The value below (and above) which are the 2.5% of the lowest (the highest) values of the distribution</em>

Because \\ \mu = 0 and \\ \sigma = 1 (and the reasons above explained), we need to find a <em>z-score</em> with a corresponding probability of 2.5% or 0.025.

As we know that this value is below \\ \mu, it is negative (the z-score is negative). Then, we can consult the <em>standard normal table</em> and find the probability 0.025 that corresponds to this specific z-score.

For this, we first find the probability of 0.025 and then look at the first row and the first column of the table, and these values are (-0.06, -1.9), respectively. Therefore, the value for the z-score = -1.96, \\ z = -1.96.

As we said before, the distribution in the question has \\ \mu = 0 and \\ \sigma = 1, the same than the standard normal distribution (of course the units are in Celsius degrees in our case).

Thus, one of the cutoff value that separates the rejected thermometers is -1.96 Celsius degrees for that 2.5% of the thermometers rejected because they have readings that are <em>too low</em>.

And because of the <em>symmetry</em> of the normal distribution, <em>z = 1.96 is the other cutoff value</em>, that is, the other lecture is 1.96 Celsius degrees, but in this case for that 2.5% of the thermometers rejected because they have readings that are <em>too high</em>. That is, in the standard normal distribution, above z = 1.96, the probability is 0.025 or \\ P(z>1.96) = 0.025 because \\ P(z.

Remember that

\\ P(z>1.96) + P(z

\\ P(z>1.96) = 1 - P(z

\\ P(z>1.96) = 1 - 0.975

\\ P(z>1.96) = 0.025

Therefore, the "two readings that are cutoff values separating the rejected thermometers from the others" are -1.96 Celsius degrees and 1.96 Celsius degrees.

The below graph shows the areas that correspond to the values below -1.96 Celsius degrees (red) (2.5% or 0.025) and the values above 1.96 Celsius degrees (blue) (2.5% or 0.025).

4 0
2 years ago
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