Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
The cost of dinner alone was $37.145
Step-by-step explanation:
15%=0.15----Convert your percentage into a decimal
43.70*0.15=6.555----Multiply the cost of dinner with the decimal
$43.70-$6.555=$37.145----Subtract the last number(6.555) from the total(43.70) to get the cost of dinner alone of $37.145 -This is making you subtract the percentage from the total!
I hope this helped!
Answer:AGC and DGH are opposite angles.
Step-by-step explanation:
So, Y+10=3x-40
Y-3x=-50-(1)
3x-40=2x
3x-2x=40
x=40
Y-3x40=-50
y-120=-50
y=-50+120
y=70
Hence, the answer is A 70°
We know that 
.
Solve using cross multiplication of the last two fractions. I will use 
to represent the width of the rectangle. 
Multiply. 
Divide both sides of the equation by 
. 
