<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
No solutions
Step-by-step explanation:
The graph does not contact the x axis
There are no real answers for this reason.
Step-by-step explanation:
the volume of a cube is
side³.
since the volume is 27 m³, the individual side lengths are then the cubic root of 27 = 3 m.
the surface area is 6 squares of 3×3 = 9m², so in total
9 × 6 = 54 m²
Answer:
8 sand bags
Step-by-step explanation:
300 - 140 = 160
160 ÷ 20 = 8
8 sand bags of 20-pounds each.
