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2 years ago

Seth is reading a long novel. if he reads 45 pages per hour, how many hours will it take him to read 585 pages?

1 answer:

6 0

It will take Seth 13 hours to read the novel.
This is true because:
You need to divide 585 by 45, and you get the answer, 13.

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Write a function rule in terms of x and y for the line that contains the points (-7.4, -9.7) and ( 8.4, 6.1) .

Karo-lina-s [1.5K]

Answer:

y = x + -2.3

x = -y - 2.3 (but why would one need this?...)

Step-by-step explanation:

(6.1 - (-9.7))/(8.4 - (-7.4)) = 15.8/15.8 = 1

6.1 = 8.4 + b

b = -2.3

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Which system of linear inequalities is graphed? {y>3x−2x+2y<4 {y≥3x−2x+2y≤4 {y≤3x−2x+2y≥4 {y<3x−2x+2y>4 A graph of a

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2 years ago

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2 years ago

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Leviafan [203]

Answer:

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Step-by-step explanation:

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2 years ago

If you have 6 cars, but there is only room in your driveway for 3 cars, in how many ways can you arrange the cars in your drivew

Svetradugi [14.3K]

If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

1. If the order does not matter, combination is used

$\left ({n} \atop {r}} \right.)=\frac{n!}{r!(n-r)!}$

Here, n=6 r=3

using formula,we get

$\left ( {{6} \atop {3}} \right)=\frac{6!}{3!3!} =5*4=20$

2. If an order is important, Permutation will be applicable

$^{n}P_{r} = \frac{n!}{(n-r)!} \\$

∴ $^{6} P_{3} =\frac{6!}{3!(6-3)!}=\frac{6!}{3!} =120$

3. the probability that the three newest cars end up parked in the driveway

P= $\frac{No. of possible outcomes for 3 cars}{total possibilities}$

= $\frac{6*4*5}{6!}$

= $\frac{120}{720}$

= $\frac{1}{6}$ ≈ 0.167

Hence, If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

Learn more about probability here brainly.com/question/6077878

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2 years ago